Queendom Tools

Hertzian Contact Pressure Calculator

Enter the inputs to see the result
Contact radius a—
Maximum pressure p_max——
Mean pressure p_mean——
Elastic approach—
Equivalent radius R—
Reduced modulus E*—

p_mean is exactly 2/3 of p_max for every load, radius and material. Values are shown to 4 significant figures.

Reference case: a 10 mm steel ball (R1 = 5 mm, E = 210 GPa, v = 0.3) on a steel flat at 1000 N gives a contact radius of 0.3191 mm and a peak pressure of 4688 MPa. The same ball over a concave R2 = −10 mm socket drops to 2953 MPa at a larger 0.4021 mm contact.

1/R  = 1/R1 + 1/R2   (1/R2 left out for a flat)
1/E* = (1 − v1²)/E1 + (1 − v2²)/E2
a    = (3·F·R / (4·E*))^(1/3)
p_max  = 3·F / (2·π·a²)
p_mean = F / (π·a²)
approach = a² / R
Units: mm, N, MPa (E in GPa × 1000).
Source: H. Hertz, 1882; K. L. Johnson, Contact Mechanics, Cambridge University Press, 1985, chapter 4.

Valid for elastic, frictionless, non-conforming contacts only. The subsurface shear stress is not given. For preliminary estimation only, not a substitute for review by a qualified/licensed engineer.

Peak contact pressure of a ball on a flat, a ball or a socket

Ball bearings, cam followers, detent balls and ball-on-flat bolted joints all carry their load on a contact patch far smaller than the parts themselves. Before picking a steel grade or a hardness specification, a mechanical designer needs a defensible peak pressure in MPa. The classical Hertz solution gives it from just the load, the radii and the elastic constants.

This calculator takes the sphere radius R1 and a second radius R2: leave it at 0 or empty for a flat, enter a positive value for a second sphere, or a negative value for a concave surface of that radius. It combines the two bodies into an equivalent radius R and a reduced modulus E*, then returns the contact radius, the maximum and mean pressure and the elastic approach.

A worked case shows the scale: a 10 mm steel ball (R1 = 5 mm, E = 210 GPa, v = 0.3) pressed onto a steel flat with 1000 N gives a contact radius of 0.3191 mm and a peak Hertzian pressure of 4688 MPa. The same ball over a concave R2 = −10 mm socket drops to 2953 MPa at a larger 0.4021 mm contact. That is why conforming geometry is the cheapest way to cut contact stress.

How to use

  1. Enter the normal load F in newtons.
  2. Enter the radius R1 of the first body in mm. Set R2 to 0 or leave it empty for a flat, a positive value for a second sphere, or a negative value for a concave surface.
  3. Enter the Young's moduli E1 and E2 in GPa for the two materials.
  4. Enter the Poisson ratios v1 and v2 (0 to 0.5).
  5. Read the contact radius, p_max, p_mean, equivalent radius, E* and approach from the result cards, which refresh as you type.

FAQ

What is the maximum Hertzian contact pressure of a 10 mm steel ball pressed onto a steel flat with 1000 N?

For R1 = 5 mm, E1 = E2 = 210 GPa and v1 = v2 = 0.3, the reduced modulus E* is 115.38 GPa, the contact radius a is 0.3191 mm, p_max is 4688 MPa (4.688 GPa), the mean pressure p_mean is 3126 MPa and the approach is 0.0204 mm.

Why is the mean contact pressure two-thirds of the maximum Hertz pressure?

Hertz gives p_max = 3F/(2πa²) and p_mean = F/(πa²), so p_mean is exactly 2/3 of p_max whatever the load, radii or materials — a 4688 MPa peak always pairs with a 3126 MPa average.

What happens if the second surface is concave instead of flat?

A negative R2 is a concave surface of that radius; the equivalent radius 1/R = 1/R1 + 1/R2 becomes larger, so the contact is bigger and the pressure lower — R1 = 5 mm on a concave R2 = −10 mm at 1000 N with steel gives R = 10 mm, a = 0.4021 mm and p_max = 2953 MPa, versus 4688 MPa on a flat.

When does the Hertz point-contact formula stop being valid?

When 1/R = 1/R1 + 1/R2 is zero or negative — i.e. a concave R2 no larger in magnitude than R1 — there is no Hertz contact and the tool reports that instead of a number; the solution also assumes elastic, frictionless, non-conforming contacts and does not give the subsurface shear stress.