Queendom Tools

Thermal Noise Floor & Receiver Sensitivity Calculator

Calculating...

Disclaimer: For preliminary estimation only, not a substitute for review by a qualified/licensed engineer.

Introduction

For RF design engineers building link budgets who need to see, in one view, how a 20 MHz channel at 290 K lands near −101 dBm before noise figure and SNR are added, and how much sensitivity those two terms cost. This calculator evaluates receiver noise floor based on Johnson-Nyquist thermal noise formula k·T·B, strictly anchoring to -174 dBm/Hz at 290 Kelvin standard room temperature.

The thermal noise floor is a fundamental limit to receiver performance, determined by the physical temperature and bandwidth. Understanding its impact is crucial for designing robust wireless communication systems. This tool provides immediate calculations, allowing engineers to quickly assess design trade-offs.

How to Use This Calculator

  1. Enter the channel or noise bandwidth B and pick its unit from the dropdown.
  2. Leave temperature at 290 K for standard room-temperature work, or type the actual front-end temperature in kelvin.
  3. Enter the receiver noise figure NF in dB and the SNR the demodulator needs to close the link.
  4. Read the thermal noise floor, the dBm/Hz density, and the resulting receiver sensitivity in dBm directly below.

FAQ

Q: How is the thermal noise floor calculated in dBm?

A: The calculator applies the Johnson-Nyquist relation k·T·B with 10*log10(1.380649e-23 × T × B × 1000); at T = 290 K and B = 1 Hz this gives exactly −174 dBm.

Q: Why is receiver sensitivity higher than the thermal noise floor?

A: Sensitivity adds the receiver noise figure and the required SNR on top of the floor: Rx_Sens = N_floor + NF + SNR, so a 3 dB noise figure and a 10 dB SNR requirement put sensitivity 13 dB above the floor.

Q: What is the noise floor for a 20 MHz channel at 290 K?

A: Starting from −174 dBm/Hz, 10*log10(20,000,000) adds about 73 dB, giving roughly −101 dBm before noise figure and SNR are applied.

Q: What happens if the receiver is not at 290 K?

A: The floor scales linearly with absolute temperature, so doubling T from 290 K to 580 K adds 10*log10(2), about 3 dB, to the noise floor.